c4ea347ace
The canonical pair on the same binary puts ModCount on 12 -> 24 exactly (zero residual), so the cost table is right on the lists that pair exercises and the rich turn's residual of 2 must sit in lists 1, 7 or 12. The only uniform per-element explanation is list 7 (colonisation) at 2 bumps -- fitted to one observation, recorded as a prediction with its falsifier. Also records the regression check on tools/aiorders_to_tcb.py: 8 shallow logs byte-identical, 4 lane-CB logs corrected (they were deep dumps whose payloads the converter had been discarding), and the canonical pair's replay unchanged. Co-Authored-By: Claude Fable 5.1 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01ARBgSooAfokKUy6wKUKEyZ |
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| .. | ||
| control-flow | ||
| objects | ||
| resolutions | ||
| subsystems | ||
| .keep.md | ||
| 00-strategy.md | ||
| 01-fingerprint.md | ||
| _template.md | ||