The operator decided on 2026-09-23 to port the live fly onto the session framework in full.
New contract legacy-gameboy-v1: the profile gameboy-legacy-fafb-v783-v1, the proof that the
legacy f64 frame clock equals the rational one, the step-by-step placement of step_frame in
lockstep-v1, the readout context (location allowed and declared), the channels decision, the
memory-image inspection and ROM AssetRef, the environment (one no-button setup frame, u8->f32
audio, DC blocker at the edge, gameboy-slots-v1), the pokered-macros-v1 executor as one object
with its task, the legacy-ratchet-rollback-v1 policy, the composition digest carrying decoder
and macro-channel configuration, legacy-transient-reset restore semantics, sugar admission with
a one-commit lag, and FLYSIM01 as format of record until RETIRE-01. PROF-02b is a stub.
Dated amendments, each citing the decision, where earlier text kept the legacy loop outside
lockstep or had no place for it: workers-v1 (telemetry, Initialize, executor, episode request
kind, admission, new section 7 extension methods), step-v1 (rollback edge, Phase B/C, clock,
episode policy, sugar lag), state-media-v1 (audio, memory-image retention, restore semantics,
format of record, section 7 ratchet), README section 4, implementation.md (AGENT-01 and ENV-01
unblocked), the MaleCNS backlog (FOUNDATION-02 split, RUNTIME-01 contract) and analysis (5.2,
5.4), and readout.md (where the location comes from).
Review found two Memory-only tests behind a README claim that every integration test runs
twice. Both are now generated by both_transports!: the one-agent composition, and the
old-epoch refusal, which is one of the three tests the old-worker-replies row cites. The
README says which single test walks both transports inside itself instead, because it
compares their traces against each other.
step-v1 section 2 gains the mid-step pause line and a dated amendment saying why it is not
a new edge: a pause requested during a transition is the ordinary
Committing(k) -> Ready(k+1) edge followed by Ready(k+1) -> Paused(k+1), because section 6
requires the transition to finish first, so the only boundary such a pause can land on is
the one the transition just committed.
